Hi together,
I have found a very easy way to calculate derivatives. You simply set f'(x) = f(x + i) / i = f(x + i) * -i. If one takes only the real part from the resulting complex term, one has the derivation.
For example:
f(x) = 3x + 2
f'(x) = (3(x + i) + 2) * -i =
(3x + 3i + 2) * -i =
3 – 3xi – 2i
Real Part 3
Second example:
f(x) = 2xx2
f'(x) = 2 (x + i) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
*-i =
4x – 2×2 * i + i
Real part 4x
Third example
f(x) = 3x-3
f'(x) = 3 (x-2 + 2xi – 1) * (x + i) * -i =
(3x-3 + 6ix-2 -3x + 3ix-2 -6x -3i) * -i =
9x-2 -3x-3 * i + 3ix -6xi + 3i-2
Real part 9x-2 – 3
Here, unfortunately, a -3 remains similar to the root function as the rest in the real part. But for linear and square equations it works quite well.
Dear greetings
Your Till